Friday 16 September 2011

Find students grades through structure

Q. Write a C program using structure to find student grades in a class. Make necessary assumption.

Ans.
Before writing program we make some assumption as following :

Maximum total marks is 500.     
  Student_percentage         Grades
     >=80                        A
     >=60                        B
     >=50                        C
     >=40                        D
     <40                         F
  
/*C program to find students grades in a class through structure */
#include<stdio.h>
#include<conio.h>
struct stud
{
  char nam[20];
  int obtain_mark;
  int per;
  char grad[5];
};
struct stud s[5];
int i;
int main()
{
 for(i=1; i<=5; i++)
 {
  printf("Enter %d student name : ",i);
  scanf("%s",&s[i].nam);
  printf("Enter %d student obtained marks = ",i);
  scanf("%d",&s[i].obtain_mark);
  fflush(stdin);
 }
 for(i=1; i<=5; i++)
   s[i].per=s[i].obtain_mark/5;
 for(i=1; i<=5; i++)
 {
  if(s[i].per>=80)
    strcpy(s[i].grad,"A");
  else if(s[i].per>=60)
    strcpy(s[i].grad,"B");
  else if(s[i].per>=50)
    strcpy(s[i].grad,"C");
  else if(s[i].per>=40)
    strcpy(s[i].grad,"D");
  else
    strcpy(s[i].grad,"F");
 }
 for(i=1; i<=5; i++)
  printf("\n%d student %s has obtained grade %s ",i,s[i].nam,s[i].grad);
 getch();
 return 0;
}
  Output of above programe :

Enter 1 student name : John
Enter 1 student obtained marks : 250
Enter 2 student name : Robert
Enter 2 student obtained marks : 410
Enter 3 student name : Isabell
Enter 3 student obtained marks : 386
Enter 4 student name : Adem
Enter 4 student obtained marks :197
Enter 5 student name :Harry
Enter 5 student obtained marks : 490 

1 student Jhon has obtained grade C
2 student Robert has obtained grade A
3 student Isabell has obtained grade B
4 student Adem has obtained grade F
5 student Harry has obtained grade A
 


C program for find student grade through structure
Figure: Screen-shot of find student grades 
through structure C program

Related programs:

  1. Get student 5 subject marks and calculate percentage and division

No comments:

Post a Comment